Revision notes
Put brackets back in: find the highest common factor of the terms and take it outside.
Aisha has 12x biscuits and 18 sweets to share into identical party packs for her brother's birthday. Using 6 packs, each gets 2x biscuits and 3 sweets: 12x + 18 = 6(2x + 3). Writing it that way is called factorising.
We know 6(2x + 3) = 12x + 18. Factorising goes the other way: from 12x + 18 back to 6(2x + 3).
Find the highest common factor (HCF) of the terms. For 12x and 18, the HCF is 6.
Put the HCF outside the bracket, and divide each term by it: 12x ÷ 6 = 2x and 18 ÷ 6 = 3. So 12x + 18 = 6(2x + 3).
🔑 Key idea: Factorising is the reverse of expanding: take out the HCF.
In 6x2 + 9x, both terms contain 3 AND x, so the HCF is 3x.
6x2 ÷ 3x = 2x and 9x ÷ 3x = 3, so 6x2 + 9x = 3x(2x + 3).
Always check by expanding: 3x × 2x + 3x × 3 = 6x2 + 9x ✓. If something common is still left inside the bracket, you haven't finished.
🔑 Key idea: Factorise completely: take out the HIGHEST common factor, then check by expanding.
Factorise completely: 12x + 15
Step 1: Find the HCF of the terms
HCF of 12 and 15 = 3
Step 2: Divide each term by the HCF
12x ÷ 3 = 4x
15 ÷ 3 = 5
12x + 15 = 3(4x + 5)
Step 3: Check by expanding
3(4x + 5) = 12x + 15 ✓
Why? Factorising is the reverse of expanding.
Answer: 3(4x + 5)
Ready to check you've got it? Scroll up and work through the lesson: the interactive visuals, practice questions and mastery check are all there.