JSS 3 · BECE preparation
JSS 3 Mathematics and BECE preparation
JSS 3 rounds off Junior Secondary Maths and prepares you for the Basic Education Certificate Examination (BECE). Topics include number bases, simple interest and financial maths, algebraic processes, simultaneous equations, Pythagoras and early trigonometry, mensuration and statistics.
Alongside lessons and practice, MathPlug gives you timed BECE-style mock exams with an estimated grade, a section-by-section breakdown and a full review of every question.
- ✓ BECE mock exams with estimated grades
- ✓ Simple interest and profit and loss
- ✓ Pythagoras' theorem
- ✓ Mean, median and mode
What you'll learn in JSS 3
9 topics across three terms, following the Nigerian (NERDC) Mathematics curriculum. 18 interactive lessons are ready now, with more being added.
First Term
Second Term
Third Term
▶ Green lessons are ready to play now.
Try some JSS 3 practice questions
Every answer below was worked out and checked by the MathPlug maths engine. Tap to see the steps.
Question 1
Evaluate (−4) × (−9).
- A−36
- B36
- C5
- D−13
Show answer and working
Step 1: Signs
negative × negative = positive
Step 2: Answer
= 36
Final answer: 36
Question 2
Express 77,284 correct to 3 significant figures.
- A77,300
- B773
- C77,200
- D77,280
Show answer and working
Step 1: Keep 3 significant figures
77,284 → the first 3 digits are 772
Step 2: Round using the next digit
The next digit is 8.
It is 5 or more, so round up.
Step 3: Fill with zeros
77,284 ≈ 77,300 (3 s.f.)
Why? The zeros keep each digit in its correct place value.
Final answer: 77,300
Question 3
If tan θ = 724 and θ is acute, find sin θ.
- A2425
- B2431
- C257
- D725
Show answer and working
Step 1: Label the triangle
tan θ = 724
opposite = 7, adjacent = 24, hypotenuse = 25
Why? The missing side comes from Pythagoras: 7² + 24² = 25².
Step 2: Find sin θ
sin θ = 7 ÷ 25 = 725
Final answer: 725